A nice way to generate a default ini file path from the file path of the executing process in C#

/// <summary>

/// Creates a default inifile in a format hostName.processName.ini , in the same directory where the 

/// </summary>

/// <returns>the file path to the init file in a string </returns>

public static string CreateProcessDefaultIniFile()

{

string strIniFilePath = String.Empty;

string strPathToExe = Environment.GetCommandLineArgs()[0];

string extension = Path.GetExtension(strPathToExe);

//string filename = Path.GetFileName(strPathToExe);

string strBaseDir = Path.GetDirectoryName(strPathToExe);

string strMachineName = System.Environment.MachineName;

string fileNameNoExtension = Path.GetFileNameWithoutExtension(strPathToExe);

//now build the default ini file path 

strIniFilePath = strBaseDir + @"\" + strMachineName + "." + fileNameNoExtension + ".ini";

return strIniFilePath;

} //eof method